Words that contain 'nh' and end in 'l'


For words that have 'nh' in and end with 'l', there are 49 entires.

6 letter words

  • inhaul
  • inhell
  • unheal
  • unhull

8 letter words

  • anhedral
  • bitanhol
  • downhaul
  • downhill
  • turnhall

9 letter words

  • clownheal
  • mijnheerl
  • unharmful
  • unhateful
  • unheedful
  • unhelpful
  • unhopeful
  • unhurtful

10 letter words

  • arsenhemol
  • unhabitual
  • unheroical
  • unhymeneal
  • unhospital

11 letter words

  • nonhabitual
  • nonheroical
  • unhealthful
  • unheretical
  • unhomicidal

12 letter words

  • duinhewassel
  • enharmonical
  • inhalational
  • inharmonical
  • nonheretical
  • unharmonical
  • unhermitical
  • unhieratical
  • unhysterical
  • unhistorical
  • unhorizontal

13 letter words

  • nonhieratical
  • nonhistorical
  • nonhomaloidal
  • unhomiletical
  • unhomological

14 letter words

  • unhypocritical
  • unhypothetical

15 letter words

  • nonhierarchical
  • nonhyperbolical
  • nonhypostatical
  • nonhistrionical

In Scrabble, what is the highest possible score possible from this list of words that contain 'nh' and end in 'l'?
One could make 'downhaul' for a total score of 15 in Scrabble.

What is an interesting word from the word combos possible ?
Arguably one of the most unusual words from this list is 'enharmonical'. It is defined as "1. (Anc. Mus.) Of or pertaining to that one of the three kinds of musical scale (diatonic, chromatic, enharmonic) recognized by the ancient Greeks, which consisted of quarter tones and major thirds, and was regarded as the most accurate. 2. (Mus.) (a) Pertaining to a change of notes to...".

Which word that has 'nh' in and ends with 'l' is the most common word?
As far as well-known words go, there's 'downhill' which is the 49586th most common word.

How many letters does the largest word on this list consist of?
'nonhierarchical' (15 characters)

In total, how many words are there using the combination specified?
It's possible to create 49 words using the combination you specified.